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1204113443331 = 34312377545847
BaseRepresentation
bin10001100001011010110…
…000010000101000000011
311021010000201212200102110
4101201122300100220003
5124212011020141311
62321055001550403
7152665024252131
oct21413260205003
94233021780373
101204113443331
11424730713a37
121754471a5403
1389716878b46
14423ca96c751
15214c5dbd8a6
hex1185ac10a03

1204113443331 has 16 divisors (see below), whose sum is σ = 1644149729024. Its totient is φ = 783439915104.

The previous prime is 1204113443327. The next prime is 1204113443353. The reversal of 1204113443331 is 1333443114021.

It is not a de Polignac number, because 1204113443331 - 22 = 1204113443327 is a prime.

It is a super-2 number, since 2×12041134433312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1204113443321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3613351 + ... + 3932496.

It is an arithmetic number, because the mean of its divisors is an integer number (102759358064).

Almost surely, 21204113443331 is an apocalyptic number.

1204113443331 is a deficient number, since it is larger than the sum of its proper divisors (440036285693).

1204113443331 is a wasteful number, since it uses less digits than its factorization.

1204113443331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7547130.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 1204113443331 its reverse (1333443114021), we get a palindrome (2537556557352).

The spelling of 1204113443331 in words is "one trillion, two hundred four billion, one hundred thirteen million, four hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 3 43 129 1237 3711 53191 159573 7545847 22637541 324471421 973414263 9334212739 28002638217 401371147777 1204113443331