Base | Representation |
---|---|
bin | 10001100001011100100… |
… | …010001110110000111010 |
3 | 11021010002211002120200021 |
4 | 101201130202032300322 |
5 | 124212041142220442 |
6 | 2321101550201054 |
7 | 152665536225361 |
oct | 21413442166072 |
9 | 4233084076607 |
10 | 1204143320122 |
11 | 42474656a8a6 |
12 | 1754551b318a |
13 | 8971cb09a12 |
14 | 423d09087d8 |
15 | 214c8820e67 |
hex | 1185c88ec3a |
1204143320122 has 4 divisors (see below), whose sum is σ = 1806214980186. Its totient is φ = 602071660060.
The previous prime is 1204143320099. The next prime is 1204143320141. The reversal of 1204143320122 is 2210233414021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1096730468001 + 107412852121 = 1047249^2 + 327739^2 .
It is a super-2 number, since 2×12041433201222 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 301035830029 + ... + 301035830032.
Almost surely, 21204143320122 is an apocalyptic number.
1204143320122 is a deficient number, since it is larger than the sum of its proper divisors (602071660064).
1204143320122 is an equidigital number, since it uses as much as digits as its factorization.
1204143320122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 602071660063.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1204143320122 its reverse (2210233414021), we get a palindrome (3414376734143).
The spelling of 1204143320122 in words is "one trillion, two hundred four billion, one hundred forty-three million, three hundred twenty thousand, one hundred twenty-two".
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