120414335431441 has 2 divisors, whose sum is σ = 120414335431442. Its totient is φ = 120414335431440.

The previous prime is 120414335431427. The next prime is 120414335431469. The reversal of 120414335431441 is 144134533414021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61364270596225 + 59050064835216 = 7833535^2 + 7684404^2 .

It is an emirp because it is prime and its reverse (144134533414021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120414335431441 - 2³³ = 120405745496849 is a prime.

It is a super-2 number, since 2×120414335431441² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120414335431394 and 120414335431403.

It is not a weakly prime, because it can be changed into another prime (120414335435441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60207167715720 + 60207167715721.

It is an arithmetic number, because the mean of its divisors is an integer number (60207167715721).

Almost surely, 2^{120414335431441} is an apocalyptic number.

It is an amenable number.

120414335431441 is a deficient number, since it is larger than the sum of its proper divisors (1).

120414335431441 is an equidigital number, since it uses as much as digits as its factorization.

120414335431441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 40.

Adding to 120414335431441 its reverse (144134533414021), we get a palindrome (264548868845462).

The spelling of 120414335431441 in words is "one hundred twenty trillion, four hundred fourteen billion, three hundred thirty-five million, four hundred thirty-one thousand, four hundred forty-one".