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1204201405041 = 3401400468347
BaseRepresentation
bin10001100001011111111…
…111110011101001110001
311021010020212101121012120
4101201133333303221301
5124212201024430131
62321111423144453
7153000143025225
oct21413777635161
94233225347176
101204201405041
11424776332968
12175470745129
138972bb660ab
14423d8508785
15214cd996496
hex1185fff3a71

1204201405041 has 4 divisors (see below), whose sum is σ = 1605601873392. Its totient is φ = 802800936692.

The previous prime is 1204201405027. The next prime is 1204201405087. The reversal of 1204201405041 is 1405041024021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1204201405041 - 211 = 1204201402993 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1204201405091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200700234171 + ... + 200700234176.

It is an arithmetic number, because the mean of its divisors is an integer number (401400468348).

Almost surely, 21204201405041 is an apocalyptic number.

It is an amenable number.

1204201405041 is a deficient number, since it is larger than the sum of its proper divisors (401400468351).

1204201405041 is an equidigital number, since it uses as much as digits as its factorization.

1204201405041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 401400468350.

The product of its (nonzero) digits is 1280, while the sum is 24.

Adding to 1204201405041 its reverse (1405041024021), we get a palindrome (2609242429062).

The spelling of 1204201405041 in words is "one trillion, two hundred four billion, two hundred one million, four hundred five thousand, forty-one".

Divisors: 1 3 401400468347 1204201405041