Base | Representation |
---|---|
bin | 10001100001100001010… |
… | …110110110000100000001 |
3 | 11021010022110022210102102 |
4 | 101201201112312010001 |
5 | 124212222400041231 |
6 | 2321114000200145 |
7 | 153000540664313 |
oct | 21414126660401 |
9 | 4233273283372 |
10 | 1204224221441 |
11 | 4247881a719a |
12 | 175478309055 |
13 | 897337c4417 |
14 | 423db5677b3 |
15 | 214d09a1acb |
hex | 118615b6101 |
1204224221441 has 2 divisors, whose sum is σ = 1204224221442. Its totient is φ = 1204224221440.
The previous prime is 1204224221413. The next prime is 1204224221449. The reversal of 1204224221441 is 1441224224021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 649199221441 + 555025000000 = 805729^2 + 745000^2 .
It is a cyclic number.
It is not a de Polignac number, because 1204224221441 - 26 = 1204224221377 is a prime.
It is not a weakly prime, because it can be changed into another prime (1204224221449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602112110720 + 602112110721.
It is an arithmetic number, because the mean of its divisors is an integer number (602112110721).
Almost surely, 21204224221441 is an apocalyptic number.
It is an amenable number.
1204224221441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204224221441 is an equidigital number, since it uses as much as digits as its factorization.
1204224221441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8192, while the sum is 29.
Adding to 1204224221441 its reverse (1441224224021), we get a palindrome (2645448445462).
The spelling of 1204224221441 in words is "one trillion, two hundred four billion, two hundred twenty-four million, two hundred twenty-one thousand, four hundred forty-one".
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