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120423153314 = 260211576657
BaseRepresentation
bin111000000100111000…
…1110111111010100010
3102111211111102000201102
41300021301313322202
53433111311401224
6131153250034402
711462124625352
oct1601161677242
9374744360642
10120423153314
1147086804502
121b409578a02
13b481a74449
145b85616b62
1531ec1de4ae
hex1c09c77ea2

120423153314 has 4 divisors (see below), whose sum is σ = 180634729974. Its totient is φ = 60211576656.

The previous prime is 120423153311. The next prime is 120423153329. The reversal of 120423153314 is 413351324021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 79260830089 + 41162323225 = 281533^2 + 202885^2 .

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (120423153311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30105788327 + ... + 30105788330.

Almost surely, 2120423153314 is an apocalyptic number.

120423153314 is a deficient number, since it is larger than the sum of its proper divisors (60211576660).

120423153314 is an equidigital number, since it uses as much as digits as its factorization.

120423153314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60211576659.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 120423153314 its reverse (413351324021), we get a palindrome (533774477335).

The spelling of 120423153314 in words is "one hundred twenty billion, four hundred twenty-three million, one hundred fifty-three thousand, three hundred fourteen".

Divisors: 1 2 60211576657 120423153314