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120423974598667 is a prime number
BaseRepresentation
bin11011011000011001100100…
…001110100111100000001011
3120210101102022211210012120001
4123120121210032213200023
5111241011244444124132
61104042002111543431
734236226231622245
oct3330314416474013
9523342284705501
10120423974598667
113540958023a413
121160ab8152ab77
135226c16a0c56c
1421a47a1339095
15ddc785bc3ce7
hex6d86643a780b

120423974598667 has 2 divisors, whose sum is σ = 120423974598668. Its totient is φ = 120423974598666.

The previous prime is 120423974598659. The next prime is 120423974598677. The reversal of 120423974598667 is 766895479324021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120423974598667 - 23 = 120423974598659 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120423974598667.

It is not a weakly prime, because it can be changed into another prime (120423974598637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60211987299333 + 60211987299334.

It is an arithmetic number, because the mean of its divisors is an integer number (60211987299334).

It is a 1-persistent number, because it is pandigital, but 2⋅120423974598667 = 240847949197334 is not.

Almost surely, 2120423974598667 is an apocalyptic number.

120423974598667 is a deficient number, since it is larger than the sum of its proper divisors (1).

120423974598667 is an equidigital number, since it uses as much as digits as its factorization.

120423974598667 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1097349120, while the sum is 73.

The spelling of 120423974598667 in words is "one hundred twenty trillion, four hundred twenty-three billion, nine hundred seventy-four million, five hundred ninety-eight thousand, six hundred sixty-seven".