Base | Representation |
---|---|
bin | 1010111100111101011110… |
… | …1001011101100010011111 |
3 | 1120122020120100102102110020 |
4 | 2233033113221131202133 |
5 | 3034300324243113043 |
6 | 41340112443243223 |
7 | 2352015115065315 |
oct | 257172751354237 |
9 | 46566510372406 |
10 | 12042411301023 |
11 | 3923181264004 |
12 | 1425a97219513 |
13 | 6947961b688c |
14 | 2d8bda50c0b5 |
15 | 15d3b6461e83 |
hex | af3d7a5d89f |
12042411301023 has 16 divisors (see below), whose sum is σ = 16066316198016. Its totient is φ = 8023391016480.
The previous prime is 12042411301009. The next prime is 12042411301027. The reversal of 12042411301023 is 32010311424021.
It is a de Polignac number, because none of the positive numbers 2k-12042411301023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12042411300984 and 12042411301002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12042411301027) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73450128 + ... + 73613898.
It is an arithmetic number, because the mean of its divisors is an integer number (1004144762376).
Almost surely, 212042411301023 is an apocalyptic number.
12042411301023 is a deficient number, since it is larger than the sum of its proper divisors (4023904896993).
12042411301023 is a wasteful number, since it uses less digits than its factorization.
12042411301023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178534.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 12042411301023 its reverse (32010311424021), we get a palindrome (44052722725044).
The spelling of 12042411301023 in words is "twelve trillion, forty-two billion, four hundred eleven million, three hundred one thousand, twenty-three".
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