Base | Representation |
---|---|
bin | 11011011000011001110100… |
… | …001110100111100000111011 |
3 | 120210101110000112220010211202 |
4 | 123120121310032213200323 |
5 | 111241012322204043141 |
6 | 1104042044501244415 |
7 | 34236236001366116 |
oct | 3330316416474073 |
9 | 523343015803752 |
10 | 120424243034171 |
11 | 354096a8814a3a |
12 | 1160b03740370b |
13 | 5226c5a50823b |
14 | 21a47c8c5357d |
15 | ddc79e54a49b |
hex | 6d86743a783b |
120424243034171 has 2 divisors, whose sum is σ = 120424243034172. Its totient is φ = 120424243034170.
The previous prime is 120424243034083. The next prime is 120424243034201. The reversal of 120424243034171 is 171430342424021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120424243034171 - 210 = 120424243033147 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (120424243094171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60212121517085 + 60212121517086.
It is an arithmetic number, because the mean of its divisors is an integer number (60212121517086).
Almost surely, 2120424243034171 is an apocalyptic number.
120424243034171 is a deficient number, since it is larger than the sum of its proper divisors (1).
120424243034171 is an equidigital number, since it uses as much as digits as its factorization.
120424243034171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129024, while the sum is 38.
Adding to 120424243034171 its reverse (171430342424021), we get a palindrome (291854585458192).
The spelling of 120424243034171 in words is "one hundred twenty trillion, four hundred twenty-four billion, two hundred forty-three million, thirty-four thousand, one hundred seventy-one".
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