Base | Representation |
---|---|
bin | 111000000101000111… |
… | …0010100111010110011 |
3 | 102111212000102222022111 |
4 | 1300022032110322303 |
5 | 3433120214042042 |
6 | 131154113550151 |
7 | 11462245212256 |
oct | 1601216247263 |
9 | 374760388274 |
10 | 120430612147 |
11 | 4708aa3942a |
12 | 1b40bb75357 |
13 | b483486461 |
14 | 5b865d909d |
15 | 31ecbb4517 |
hex | 1c0a394eb3 |
120430612147 has 2 divisors, whose sum is σ = 120430612148. Its totient is φ = 120430612146.
The previous prime is 120430612117. The next prime is 120430612163. The reversal of 120430612147 is 741216034021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120430612147 - 227 = 120296394419 is a prime.
It is a super-2 number, since 2×1204306121472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120430612117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60215306073 + 60215306074.
It is an arithmetic number, because the mean of its divisors is an integer number (60215306074).
Almost surely, 2120430612147 is an apocalyptic number.
120430612147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120430612147 is an equidigital number, since it uses as much as digits as its factorization.
120430612147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 120430612147 its reverse (741216034021), we get a palindrome (861646646168).
The spelling of 120430612147 in words is "one hundred twenty billion, four hundred thirty million, six hundred twelve thousand, one hundred forty-seven".
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