12043321104433 has 2 divisors, whose sum is σ = 12043321104434. Its totient is φ = 12043321104432.

The previous prime is 12043321104427. The next prime is 12043321104469. The reversal of 12043321104433 is 33440112334021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10612263976609 + 1431057127824 = 3257647^2 + 1196268^2 .

It is a cyclic number.

It is not a de Polignac number, because 12043321104433 - 2⁵ = 12043321104401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12043321104395 and 12043321104404.

It is not a weakly prime, because it can be changed into another prime (12043321104403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021660552216 + 6021660552217.

It is an arithmetic number, because the mean of its divisors is an integer number (6021660552217).

Almost surely, 2^{12043321104433} is an apocalyptic number.

It is an amenable number.

12043321104433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12043321104433 is an equidigital number, since it uses as much as digits as its factorization.

12043321104433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 12043321104433 its reverse (33440112334021), we get a palindrome (45483433438454).

The spelling of 12043321104433 in words is "twelve trillion, forty-three billion, three hundred twenty-one million, one hundred four thousand, four hundred thirty-three".