120433415133113 has 4 divisors (see below), whose sum is σ = 120437601092688. Its totient is φ = 120429229173540.

The previous prime is 120433415133079. The next prime is 120433415133127. The reversal of 120433415133113 is 311331514334021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120433415133113 - 2²² = 120433410938809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120433415133173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2092936631 + ... + 2092994172.

It is an arithmetic number, because the mean of its divisors is an integer number (30109400273172).

Almost surely, 2^{120433415133113} is an apocalyptic number.

It is an amenable number.

120433415133113 is a deficient number, since it is larger than the sum of its proper divisors (4185959575).

120433415133113 is an equidigital number, since it uses as much as digits as its factorization.

120433415133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4185959574.

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 120433415133113 its reverse (311331514334021), we get a palindrome (431764929467134).

The spelling of 120433415133113 in words is "one hundred twenty trillion, four hundred thirty-three billion, four hundred fifteen million, one hundred thirty-three thousand, one hundred thirteen".