120440113 has 4 divisors (see below), whose sum is σ = 120478320. Its totient is φ = 120401908.

The previous prime is 120440081. The next prime is 120440129. The reversal of 120440113 is 311044021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311044021 = 73 ⋅4260877.

It is a cyclic number.

It is not a de Polignac number, because 120440113 - 2⁵ = 120440081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120440713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13903 + ... + 20836.

It is an arithmetic number, because the mean of its divisors is an integer number (30119580).

Almost surely, 2^120440113 is an apocalyptic number.

It is an amenable number.

120440113 is a deficient number, since it is larger than the sum of its proper divisors (38207).

120440113 is an equidigital number, since it uses as much as digits as its factorization.

120440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38206.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 120440113 is about 10974.5210829448. The cubic root of 120440113 is about 493.8446858308.

Adding to 120440113 its reverse (311044021), we get a palindrome (431484134).

The spelling of 120440113 in words is "one hundred twenty million, four hundred forty thousand, one hundred thirteen".