Base | Representation |
---|---|
bin | 111000000101100001… |
… | …1000101111100010001 |
3 | 102111212222110201122101 |
4 | 1300023003011330101 |
5 | 3433132234210213 |
6 | 131155330240401 |
7 | 11462503612525 |
oct | 1601303057421 |
9 | 374788421571 |
10 | 120444444433 |
11 | 47097826875 |
12 | 1b414726101 |
13 | b4862ba441 |
14 | 5b88399d85 |
15 | 31edee7bdd |
hex | 1c0b0c5f11 |
120444444433 has 2 divisors, whose sum is σ = 120444444434. Its totient is φ = 120444444432.
The previous prime is 120444444409. The next prime is 120444444437. The reversal of 120444444433 is 334444444021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75044767249 + 45399677184 = 273943^2 + 213072^2 .
It is a cyclic number.
It is not a de Polignac number, because 120444444433 - 25 = 120444444401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120444444392 and 120444444401.
It is not a weakly prime, because it can be changed into another prime (120444444437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60222222216 + 60222222217.
It is an arithmetic number, because the mean of its divisors is an integer number (60222222217).
Almost surely, 2120444444433 is an apocalyptic number.
It is an amenable number.
120444444433 is a deficient number, since it is larger than the sum of its proper divisors (1).
120444444433 is an equidigital number, since it uses as much as digits as its factorization.
120444444433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 294912, while the sum is 37.
Adding to 120444444433 its reverse (334444444021), we get a palindrome (454888888454).
The spelling of 120444444433 in words is "one hundred twenty billion, four hundred forty-four million, four hundred forty-four thousand, four hundred thirty-three".
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