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12050503204153 is a prime number
BaseRepresentation
bin1010111101011011100111…
…1101100111110100111001
31120200000110021202200202011
42233112321331213310321
53034413412310013103
641343531425005521
72352422463115531
oct257267175476471
946600407680664
1012050503204153
1139266539a2657
1214275751838a1
13695485796c3b
142d936709a4c1
1515d6dba62d6d
hexaf5b9f67d39

12050503204153 has 2 divisors, whose sum is σ = 12050503204154. Its totient is φ = 12050503204152.

The previous prime is 12050503204073. The next prime is 12050503204171. The reversal of 12050503204153 is 35140230505021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12006037890729 + 44465313424 = 3464973^2 + 210868^2 .

It is a cyclic number.

It is not a de Polignac number, because 12050503204153 - 213 = 12050503195961 is a prime.

It is not a weakly prime, because it can be changed into another prime (12050503208153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6025251602076 + 6025251602077.

It is an arithmetic number, because the mean of its divisors is an integer number (6025251602077).

Almost surely, 212050503204153 is an apocalyptic number.

It is an amenable number.

12050503204153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12050503204153 is an equidigital number, since it uses as much as digits as its factorization.

12050503204153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 12050503204153 its reverse (35140230505021), we get a palindrome (47190733709174).

The spelling of 12050503204153 in words is "twelve trillion, fifty billion, five hundred three million, two hundred four thousand, one hundred fifty-three".