Base | Representation |
---|---|
bin | 1010111101011101100100… |
… | …0000110011010001001011 |
3 | 1120200001210120222112020112 |
4 | 2233113121000303101023 |
5 | 3034420444134144042 |
6 | 41344055234144535 |
7 | 2352441416662241 |
oct | 257273100632113 |
9 | 46601716875215 |
10 | 12051024131147 |
11 | 39268a0a52831 |
12 | 142769b72214b |
13 | 695539698371 |
14 | 2d93b633c791 |
15 | 15d71c661982 |
hex | af5d903344b |
12051024131147 has 2 divisors, whose sum is σ = 12051024131148. Its totient is φ = 12051024131146.
The previous prime is 12051024131119. The next prime is 12051024131171. The reversal of 12051024131147 is 74113142015021.
12051024131147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12051024131147 - 238 = 11776146224203 is a prime.
It is not a weakly prime, because it can be changed into another prime (12051024131177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6025512065573 + 6025512065574.
It is an arithmetic number, because the mean of its divisors is an integer number (6025512065574).
Almost surely, 212051024131147 is an apocalyptic number.
12051024131147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12051024131147 is an equidigital number, since it uses as much as digits as its factorization.
12051024131147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 32.
Adding to 12051024131147 its reverse (74113142015021), we get a palindrome (86164166146168).
The spelling of 12051024131147 in words is "twelve trillion, fifty-one billion, twenty-four million, one hundred thirty-one thousand, one hundred forty-seven".
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