12051453433 has 4 divisors (see below), whose sum is σ = 12052164340. Its totient is φ = 12050742528.

The previous prime is 12051453373. The next prime is 12051453439. The reversal of 12051453433 is 33435415021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33435415021 = 487 ⋅68655883.

It can be written as a sum of positive squares in 2 ways, for example, as 3917758464 + 8133694969 = 62592^2 + 90187^2 .

It is a cyclic number.

It is not a de Polignac number, because 12051453433 - 2²¹ = 12049356281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12051453395 and 12051453404.

It is not an unprimeable number, because it can be changed into a prime (12051453439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 329388 + ... + 364141.

It is an arithmetic number, because the mean of its divisors is an integer number (3013041085).

Almost surely, 2^12051453433 is an apocalyptic number.

It is an amenable number.

12051453433 is a deficient number, since it is larger than the sum of its proper divisors (710907).

12051453433 is an equidigital number, since it uses as much as digits as its factorization.

12051453433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 710906.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 12051453433 its reverse (33435415021), we get a palindrome (45486868454).

The spelling of 12051453433 in words is "twelve billion, fifty-one million, four hundred fifty-three thousand, four hundred thirty-three".