Base | Representation |
---|---|
bin | 1010111101100110000110… |
… | …0010011110111111100011 |
3 | 1120200021201020000120101022 |
4 | 2233121201202132333203 |
5 | 3034440142023143441 |
6 | 41345114420200055 |
7 | 2352552242115653 |
oct | 257314142367743 |
9 | 46607636016338 |
10 | 12053314662371 |
11 | 3927866996844 |
12 | 142801a83902b |
13 | 6958130a6698 |
14 | 2d9552624363 |
15 | 15d8037b284b |
hex | af66189efe3 |
12053314662371 has 2 divisors, whose sum is σ = 12053314662372. Its totient is φ = 12053314662370.
The previous prime is 12053314662353. The next prime is 12053314662377. The reversal of 12053314662371 is 17326641335021.
It is a strong prime.
It is an emirp because it is prime and its reverse (17326641335021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12053314662371 - 214 = 12053314645987 is a prime.
It is not a weakly prime, because it can be changed into another prime (12053314662377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6026657331185 + 6026657331186.
It is an arithmetic number, because the mean of its divisors is an integer number (6026657331186).
Almost surely, 212053314662371 is an apocalyptic number.
12053314662371 is a deficient number, since it is larger than the sum of its proper divisors (1).
12053314662371 is an equidigital number, since it uses as much as digits as its factorization.
12053314662371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 44.
Adding to 12053314662371 its reverse (17326641335021), we get a palindrome (29379955997392).
The spelling of 12053314662371 in words is "twelve trillion, fifty-three billion, three hundred fourteen million, six hundred sixty-two thousand, three hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •