Base | Representation |
---|---|
bin | 1010111110001111001001… |
… | …1011010110010010111011 |
3 | 1120201100011021112012100222 |
4 | 2233203302123112102323 |
5 | 3040130224332011101 |
6 | 41354140145250255 |
7 | 2353422323045261 |
oct | 257436233262273 |
9 | 46640137465328 |
10 | 12064335422651 |
11 | 3931501914096 |
12 | 142a19563398b |
13 | 69687b3bc505 |
14 | 2d9cba17a431 |
15 | 15dc4b0a301b |
hex | af8f26d64bb |
12064335422651 has 2 divisors, whose sum is σ = 12064335422652. Its totient is φ = 12064335422650.
The previous prime is 12064335422609. The next prime is 12064335422683. The reversal of 12064335422651 is 15622453346021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12064335422651 is a prime.
It is not a weakly prime, because it can be changed into another prime (12064335421651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6032167711325 + 6032167711326.
It is an arithmetic number, because the mean of its divisors is an integer number (6032167711326).
Almost surely, 212064335422651 is an apocalyptic number.
12064335422651 is a deficient number, since it is larger than the sum of its proper divisors (1).
12064335422651 is an equidigital number, since it uses as much as digits as its factorization.
12064335422651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 44.
Adding to 12064335422651 its reverse (15622453346021), we get a palindrome (27686788768672).
The spelling of 12064335422651 in words is "twelve trillion, sixty-four billion, three hundred thirty-five million, four hundred twenty-two thousand, six hundred fifty-one".
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