Base | Representation |
---|---|
bin | 10001100110000110001… |
… | …111111011111011011011 |
3 | 11021120222220201110020112 |
4 | 101212012033323323123 |
5 | 124302303330302442 |
6 | 2323245334314535 |
7 | 153233366365214 |
oct | 21460617737333 |
9 | 4246886643215 |
10 | 1209138134747 |
11 | 426879a55a74 |
12 | 176409ab8a4b |
13 | 8a03787132a |
14 | 4274601a40b |
15 | 216bc0a1082 |
hex | 119863fbedb |
1209138134747 has 2 divisors, whose sum is σ = 1209138134748. Its totient is φ = 1209138134746.
The previous prime is 1209138134723. The next prime is 1209138134753. The reversal of 1209138134747 is 7474318319021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1209138134747 - 224 = 1209121357531 is a prime.
It is a super-3 number, since 3×12091381347473 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1209138134695 and 1209138134704.
It is not a weakly prime, because it can be changed into another prime (1209138134717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 604569067373 + 604569067374.
It is an arithmetic number, because the mean of its divisors is an integer number (604569067374).
Almost surely, 21209138134747 is an apocalyptic number.
1209138134747 is a deficient number, since it is larger than the sum of its proper divisors (1).
1209138134747 is an equidigital number, since it uses as much as digits as its factorization.
1209138134747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1016064, while the sum is 50.
The spelling of 1209138134747 in words is "one trillion, two hundred nine billion, one hundred thirty-eight million, one hundred thirty-four thousand, seven hundred forty-seven".
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