Base | Representation |
---|---|
bin | 11011100000110010001000… |
… | …101100110011110110010001 |
3 | 120212102111102212011021210111 |
4 | 123200302020230303312101 |
5 | 111324431212200022433 |
6 | 1105202403434201321 |
7 | 34325653401646333 |
oct | 3340621054636621 |
9 | 525374385137714 |
10 | 121000112110993 |
11 | 3561094a902815 |
12 | 116a2770883241 |
13 | 52693529b967b |
14 | 21c461833b453 |
15 | dec755b64dcd |
hex | 6e0c88b33d91 |
121000112110993 has 2 divisors, whose sum is σ = 121000112110994. Its totient is φ = 121000112110992.
The previous prime is 121000112110987. The next prime is 121000112111077. The reversal of 121000112110993 is 399011211000121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 64621533717504 + 56378578393489 = 8038752^2 + 7508567^2 .
It is a cyclic number.
It is not a de Polignac number, because 121000112110993 - 217 = 121000111979921 is a prime.
It is not a weakly prime, because it can be changed into another prime (121000112110963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500056055496 + 60500056055497.
It is an arithmetic number, because the mean of its divisors is an integer number (60500056055497).
Almost surely, 2121000112110993 is an apocalyptic number.
It is an amenable number.
121000112110993 is a deficient number, since it is larger than the sum of its proper divisors (1).
121000112110993 is an equidigital number, since it uses as much as digits as its factorization.
121000112110993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 31.
The spelling of 121000112110993 in words is "one hundred twenty-one trillion, one hundred twelve million, one hundred ten thousand, nine hundred ninety-three".
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