Base | Representation |
---|---|
bin | 11011100000110010001001… |
… | …001111001011010100000011 |
3 | 120212102111110111002222211112 |
4 | 123200302021033023110003 |
5 | 111324431222001320003 |
6 | 1105202404355233535 |
7 | 34325653541350556 |
oct | 3340621117132403 |
9 | 525374414088745 |
10 | 121000121120003 |
11 | 356109549a6384 |
12 | 116a27738a88ab |
13 | 5269354822148 |
14 | 21c461960469d |
15 | dec7568443d8 |
hex | 6e0c893cb503 |
121000121120003 has 2 divisors, whose sum is σ = 121000121120004. Its totient is φ = 121000121120002.
The previous prime is 121000121119987. The next prime is 121000121120009. The reversal of 121000121120003 is 300021121000121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121000121120003 - 24 = 121000121119987 is a prime.
It is a super-2 number, since 2×1210001211200032 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 121000121120003.
It is not a weakly prime, because it can be changed into another prime (121000121120009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500060560001 + 60500060560002.
It is an arithmetic number, because the mean of its divisors is an integer number (60500060560002).
Almost surely, 2121000121120003 is an apocalyptic number.
121000121120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
121000121120003 is an equidigital number, since it uses as much as digits as its factorization.
121000121120003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 121000121120003 its reverse (300021121000121), we get a palindrome (421021242120124).
The spelling of 121000121120003 in words is "one hundred twenty-one trillion, one hundred twenty-one million, one hundred twenty thousand, three".
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