Base | Representation |
---|---|
bin | 10001100110111010001… |
… | …101111010110011011011 |
3 | 11021200020200022212110001 |
4 | 101212322031322303123 |
5 | 124311100031133313 |
6 | 2323512042033431 |
7 | 153264114322663 |
oct | 21467215726333 |
9 | 4250220285401 |
10 | 1210010021083 |
11 | 427187126096 |
12 | 176611aa8877 |
13 | 8a1463a34c6 |
14 | 427c9b391a3 |
15 | 2171d8c7add |
hex | 119ba37acdb |
1210010021083 has 2 divisors, whose sum is σ = 1210010021084. Its totient is φ = 1210010021082.
The previous prime is 1210010021063. The next prime is 1210010021111. The reversal of 1210010021083 is 3801200100121.
It is a weak prime.
It is an emirp because it is prime and its reverse (3801200100121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1210010021083 is a prime.
It is a super-2 number, since 2×12100100210832 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1210010021083.
It is not a weakly prime, because it can be changed into another prime (1210010021023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605005010541 + 605005010542.
It is an arithmetic number, because the mean of its divisors is an integer number (605005010542).
Almost surely, 21210010021083 is an apocalyptic number.
1210010021083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210010021083 is an equidigital number, since it uses as much as digits as its factorization.
1210010021083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
The spelling of 1210010021083 in words is "one trillion, two hundred ten billion, ten million, twenty-one thousand, eighty-three".
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