Base | Representation |
---|---|
bin | 11011100000110011000011… |
… | …101001100000100001001011 |
3 | 120212102120222210010012012212 |
4 | 123200303003221200201023 |
5 | 111324440223340214011 |
6 | 1105203045523455335 |
7 | 34326020041143446 |
oct | 3340630351404113 |
9 | 525376883105185 |
10 | 121001101101131 |
11 | 35611308096739 |
12 | 116a29a7b2754b |
13 | 526947c870434 |
14 | 21c46ad82065d |
15 | dec7b28be08b |
hex | 6e0cc3a6084b |
121001101101131 has 2 divisors, whose sum is σ = 121001101101132. Its totient is φ = 121001101101130.
The previous prime is 121001101101053. The next prime is 121001101101149. The reversal of 121001101101131 is 131101101100121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121001101101131 is a prime.
It is a super-2 number, since 2×1210011011011312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121001101101151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500550550565 + 60500550550566.
It is an arithmetic number, because the mean of its divisors is an integer number (60500550550566).
Almost surely, 2121001101101131 is an apocalyptic number.
121001101101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
121001101101131 is an equidigital number, since it uses as much as digits as its factorization.
121001101101131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 121001101101131 its reverse (131101101100121), we get a palindrome (252102202201252).
The spelling of 121001101101131 in words is "one hundred twenty-one trillion, one billion, one hundred one million, one hundred one thousand, one hundred thirty-one".
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