121001212113 has 4 divisors (see below), whose sum is σ = 161334949488. Its totient is φ = 80667474740.

The previous prime is 121001212099. The next prime is 121001212153. The reversal of 121001212113 is 311212100121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121001212113 - 2⁴ = 121001212097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121001212092 and 121001212101.

It is not an unprimeable number, because it can be changed into a prime (121001212153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20166868683 + ... + 20166868688.

It is an arithmetic number, because the mean of its divisors is an integer number (40333737372).

Almost surely, 2^121001212113 is an apocalyptic number.

It is an amenable number.

121001212113 is a deficient number, since it is larger than the sum of its proper divisors (40333737375).

121001212113 is an equidigital number, since it uses as much as digits as its factorization.

121001212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40333737374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 121001212113 its reverse (311212100121), we get a palindrome (432213312234).

The spelling of 121001212113 in words is "one hundred twenty-one billion, one million, two hundred twelve thousand, one hundred thirteen".