12100132111323 has 4 divisors (see below), whose sum is σ = 16133509481768. Its totient is φ = 8066754740880.

The previous prime is 12100132111231. The next prime is 12100132111351. The reversal of 12100132111323 is 32311123100121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12100132111323 - 2¹⁰ = 12100132110299 is a prime.

It is a super-2 number, since 2×12100132111323² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12100132111323.

It is not an unprimeable number, because it can be changed into a prime (12100132111373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2016688685218 + ... + 2016688685223.

It is an arithmetic number, because the mean of its divisors is an integer number (4033377370442).

Almost surely, 2^{12100132111323} is an apocalyptic number.

12100132111323 is a deficient number, since it is larger than the sum of its proper divisors (4033377370445).

12100132111323 is an equidigital number, since it uses as much as digits as its factorization.

12100132111323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4033377370444.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 12100132111323 its reverse (32311123100121), we get a palindrome (44411255211444).

The spelling of 12100132111323 in words is "twelve trillion, one hundred billion, one hundred thirty-two million, one hundred eleven thousand, three hundred twenty-three".