Search a number
-
+
121001414113 = 3125931505311
BaseRepresentation
bin111000010110000111…
…1110000110111100001
3102120022210111201102001
41300230033300313201
53440302330222423
6131330504124001
711512346023036
oct1605417606741
9376283451361
10121001414113
1147353164398
121b54b166601
13b5447cb0b8
145bdc34138d
153232d65cad
hex1c2c3f0de1

121001414113 has 8 divisors (see below), whose sum is σ = 124952938496. Its totient is φ = 117052905600.

The previous prime is 121001414069. The next prime is 121001414119. The reversal of 121001414113 is 311414100121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121001414113 - 229 = 120464543201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121001414119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 672273 + ... + 833038.

It is an arithmetic number, because the mean of its divisors is an integer number (15619117312).

Almost surely, 2121001414113 is an apocalyptic number.

It is an amenable number.

121001414113 is a deficient number, since it is larger than the sum of its proper divisors (3951524383).

121001414113 is a wasteful number, since it uses less digits than its factorization.

121001414113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1507935.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 121001414113 its reverse (311414100121), we get a palindrome (432415514234).

The spelling of 121001414113 in words is "one hundred twenty-one billion, one million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 31 2593 80383 1505311 46664641 3903271423 121001414113