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121002121110251 is a prime number
BaseRepresentation
bin11011100000110100000000…
…011100100010001011101011
3120212102200121212110000200102
4123200310000130202023223
5111324444321001012001
61105203335042100015
734326054235112123
oct3340640034421353
9525380555400612
10121002121110251
1135611790936687
12116a303164a60b
1352695b2c94c24
1421c4769099c83
15dec822203e6b
hex6e0d007222eb

121002121110251 has 2 divisors, whose sum is σ = 121002121110252. Its totient is φ = 121002121110250.

The previous prime is 121002121110197. The next prime is 121002121110257. The reversal of 121002121110251 is 152011121200121.

It is a strong prime.

It is an emirp because it is prime and its reverse (152011121200121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121002121110251 - 210 = 121002121109227 is a prime.

It is not a weakly prime, because it can be changed into another prime (121002121110257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501060555125 + 60501060555126.

It is an arithmetic number, because the mean of its divisors is an integer number (60501060555126).

Almost surely, 2121002121110251 is an apocalyptic number.

121002121110251 is a deficient number, since it is larger than the sum of its proper divisors (1).

121002121110251 is an equidigital number, since it uses as much as digits as its factorization.

121002121110251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 20.

Adding to 121002121110251 its reverse (152011121200121), we get a palindrome (273013242310372).

The spelling of 121002121110251 in words is "one hundred twenty-one trillion, two billion, one hundred twenty-one million, one hundred ten thousand, two hundred fifty-one".