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121002121113 = 3125932036569
BaseRepresentation
bin111000010110001001…
…0011101011110011001
3102120022211211122020020
41300230102131132121
53440303020333423
6131330531221053
711512355026206
oct1605422353631
9376284748206
10121002121113
11473535a7595
121b54b447789
13b5449b7b43
145bdc486cad
153232e554e3
hex1c2c49d799

121002121113 has 8 divisors (see below), whose sum is σ = 161464312800. Its totient is φ = 80604005088.

The previous prime is 121002121109. The next prime is 121002121139. The reversal of 121002121113 is 311121200121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 121002121113 - 22 = 121002121109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121002121092 and 121002121101.

It is not an unprimeable number, because it can be changed into a prime (121002121213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16014508 + ... + 16022061.

It is an arithmetic number, because the mean of its divisors is an integer number (20183039100).

Almost surely, 2121002121113 is an apocalyptic number.

It is an amenable number.

121002121113 is a deficient number, since it is larger than the sum of its proper divisors (40462191687).

121002121113 is a wasteful number, since it uses less digits than its factorization.

121002121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32037831.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 121002121113 its reverse (311121200121), we get a palindrome (432123321234).

The spelling of 121002121113 in words is "one hundred twenty-one billion, two million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 1259 3777 32036569 96109707 40334040371 121002121113