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1210022110081 is a prime number
BaseRepresentation
bin10001100110111010111…
…100000010001110000001
311021200021112002001102201
4101212322330002032001
5124311111130010311
62323513153113201
7153264322142611
oct21467274021601
94250245061381
101210022110081
11427192a327a4
12176615b58801
138a148a46b65
14427cb5a4a41
152171e9b49c1
hex119baf02381

1210022110081 has 2 divisors, whose sum is σ = 1210022110082. Its totient is φ = 1210022110080.

The previous prime is 1210022110069. The next prime is 1210022110097. The reversal of 1210022110081 is 1800112200121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 844118100081 + 365904010000 = 918759^2 + 604900^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210022110081 - 213 = 1210022101889 is a prime.

It is a super-2 number, since 2×12100221100812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1210022110051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605011055040 + 605011055041.

It is an arithmetic number, because the mean of its divisors is an integer number (605011055041).

Almost surely, 21210022110081 is an apocalyptic number.

It is an amenable number.

1210022110081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210022110081 is an equidigital number, since it uses as much as digits as its factorization.

1210022110081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 19.

The spelling of 1210022110081 in words is "one trillion, two hundred ten billion, twenty-two million, one hundred ten thousand, eighty-one".