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121003121331993 = 353761025920327
BaseRepresentation
bin11011100000110100111100…
…000100000100111100011001
3120212102210012120112112222010
4123200310330010010330121
5111330003343030110433
61105204022212220133
734326121101625365
oct3340647404047431
9525383176475863
10121003121331993
11356121544a101a
12116a327060a649
13526971227c004
1421c4821c642a5
15dec87ee2ae63
hex6e0d3c104f19

121003121331993 has 8 divisors (see below), whose sum is σ = 164381598790848. Its totient is φ = 79146695713904.

The previous prime is 121003121331977. The next prime is 121003121332007. The reversal of 121003121331993 is 399133121300121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121003121331993 - 24 = 121003121331977 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (121003121331943) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 380512960005 + ... + 380512960322.

It is an arithmetic number, because the mean of its divisors is an integer number (20547699848856).

Almost surely, 2121003121331993 is an apocalyptic number.

It is an amenable number.

121003121331993 is a deficient number, since it is larger than the sum of its proper divisors (43378477458855).

121003121331993 is an equidigital number, since it uses as much as digits as its factorization.

121003121331993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 761025920383.

The product of its (nonzero) digits is 26244, while the sum is 39.

The spelling of 121003121331993 in words is "one hundred twenty-one trillion, three billion, one hundred twenty-one million, three hundred thirty-one thousand, nine hundred ninety-three".

Divisors: 1 3 53 159 761025920327 2283077760981 40334373777331 121003121331993