121003123301233 has 4 divisors (see below), whose sum is σ = 127371708738160. Its totient is φ = 114634537864308.

The previous prime is 121003123301219. The next prime is 121003123301237. The reversal of 121003123301233 is 332103321300121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121003123301233 - 2⁵ = 121003123301201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121003123301198 and 121003123301207.

It is not an unprimeable number, because it can be changed into a prime (121003123301237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3184292718435 + ... + 3184292718472.

It is an arithmetic number, because the mean of its divisors is an integer number (31842927184540).

Almost surely, 2^{121003123301233} is an apocalyptic number.

It is an amenable number.

121003123301233 is a deficient number, since it is larger than the sum of its proper divisors (6368585436927).

121003123301233 is an equidigital number, since it uses as much as digits as its factorization.

121003123301233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6368585436926.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 121003123301233 its reverse (332103321300121), we get a palindrome (453106444601354).

The spelling of 121003123301233 in words is "one hundred twenty-one trillion, three billion, one hundred twenty-three million, three hundred one thousand, two hundred thirty-three".