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121003132303307 is a prime number
BaseRepresentation
bin11011100000110100111100…
…101101111011011111001011
3120212102210020100011221210002
4123200310330231323133023
5111330003403332201212
61105204023243313215
734326121264111622
oct3340647455733713
9525383210157702
10121003132303307
113561215a704a21
12116a327421b80b
135269714620a07
1421c48234bc6b9
15dec880d96ac2
hex6e0d3cb7b7cb

121003132303307 has 2 divisors, whose sum is σ = 121003132303308. Its totient is φ = 121003132303306.

The previous prime is 121003132303223. The next prime is 121003132303343. The reversal of 121003132303307 is 703303231300121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121003132303307 - 232 = 120998837336011 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121003132303307.

It is not a weakly prime, because it can be changed into another prime (121003132303387) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60501566151653 + 60501566151654.

It is an arithmetic number, because the mean of its divisors is an integer number (60501566151654).

Almost surely, 2121003132303307 is an apocalyptic number.

121003132303307 is a deficient number, since it is larger than the sum of its proper divisors (1).

121003132303307 is an equidigital number, since it uses as much as digits as its factorization.

121003132303307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 29.

Adding to 121003132303307 its reverse (703303231300121), we get a palindrome (824306363603428).

The spelling of 121003132303307 in words is "one hundred twenty-one trillion, three billion, one hundred thirty-two million, three hundred three thousand, three hundred seven".