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121004354137 is a prime number
BaseRepresentation
bin111000010110001101…
…0111110101001011001
3102120100000001002100211
41300230122332221121
53440304103313022
6131331051131121
711512413016402
oct1605432765131
9376300032324
10121004354137
1147354892267
121b550143aa1
13b5452ba364
145bdc8a89a9
153233246e77
hex1c2c6bea59

121004354137 has 2 divisors, whose sum is σ = 121004354138. Its totient is φ = 121004354136.

The previous prime is 121004354117. The next prime is 121004354221. The reversal of 121004354137 is 731453400121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65067847056 + 55936507081 = 255084^2 + 236509^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121004354137 is a prime.

It is a super-2 number, since 2×1210043541372 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121004354099 and 121004354108.

It is not a weakly prime, because it can be changed into another prime (121004354117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60502177068 + 60502177069.

It is an arithmetic number, because the mean of its divisors is an integer number (60502177069).

Almost surely, 2121004354137 is an apocalyptic number.

It is an amenable number.

121004354137 is a deficient number, since it is larger than the sum of its proper divisors (1).

121004354137 is an equidigital number, since it uses as much as digits as its factorization.

121004354137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 121004354137 its reverse (731453400121), we get a palindrome (852457754258).

The spelling of 121004354137 in words is "one hundred twenty-one billion, four million, three hundred fifty-four thousand, one hundred thirty-seven".