Base | Representation |
---|---|
bin | 111000010110001101… |
… | …0111110110001011011 |
3 | 102120100000001010001212 |
4 | 1300230122332301123 |
5 | 3440304103322101 |
6 | 131331051133335 |
7 | 11512413021035 |
oct | 1605432766133 |
9 | 376300033055 |
10 | 121004354651 |
11 | 47354892694 |
12 | 1b55014424b |
13 | b5452ba66b |
14 | 5bdc8a8c55 |
15 | 32332471bb |
hex | 1c2c6bec5b |
121004354651 has 2 divisors, whose sum is σ = 121004354652. Its totient is φ = 121004354650.
The previous prime is 121004354641. The next prime is 121004354657. The reversal of 121004354651 is 156453400121.
It is a strong prime.
It is an emirp because it is prime and its reverse (156453400121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121004354651 - 234 = 103824485467 is a prime.
It is a super-3 number, since 3×1210043546513 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (121004354657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60502177325 + 60502177326.
It is an arithmetic number, because the mean of its divisors is an integer number (60502177326).
Almost surely, 2121004354651 is an apocalyptic number.
121004354651 is a deficient number, since it is larger than the sum of its proper divisors (1).
121004354651 is an equidigital number, since it uses as much as digits as its factorization.
121004354651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 121004354651 its reverse (156453400121), we get a palindrome (277457754772).
The spelling of 121004354651 in words is "one hundred twenty-one billion, four million, three hundred fifty-four thousand, six hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •