Base | Representation |
---|---|
bin | 10110100010011111… |
… | …00000111110111001 |
3 | 1011020022010001010012 |
4 | 23101033200332321 |
5 | 144240203034433 |
6 | 5320414231305 |
7 | 605601020465 |
oct | 132117407671 |
9 | 34208101105 |
10 | 12100439993 |
11 | 514a423734 |
12 | 24184b5535 |
13 | 11aac00685 |
14 | 82b0c54a5 |
15 | 4ac4b0848 |
hex | 2d13e0fb9 |
12100439993 has 2 divisors, whose sum is σ = 12100439994. Its totient is φ = 12100439992.
The previous prime is 12100439957. The next prime is 12100440007. The reversal of 12100439993 is 39993400121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11854201129 + 246238864 = 108877^2 + 15692^2 .
It is a cyclic number.
It is not a de Polignac number, because 12100439993 - 216 = 12100374457 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12100439993.
It is not a weakly prime, because it can be changed into another prime (12100439933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050219996 + 6050219997.
It is an arithmetic number, because the mean of its divisors is an integer number (6050219997).
Almost surely, 212100439993 is an apocalyptic number.
It is an amenable number.
12100439993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100439993 is an equidigital number, since it uses as much as digits as its factorization.
12100439993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 12100439993 in words is "twelve billion, one hundred million, four hundred thirty-nine thousand, nine hundred ninety-three".
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