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12101022111323 is a prime number
BaseRepresentation
bin1011000000010111110100…
…0111111101011001011011
31120211211212001000002012002
42300011331013331121123
53041230343130030243
641423044404311215
72356161415543265
oct260057507753133
946754761002162
1012101022111323
113946018566302
1214353139a250b
1369a176bab912
142db99a6a4b35
1515eb96c57eb8
hexb017d1fd65b

12101022111323 has 2 divisors, whose sum is σ = 12101022111324. Its totient is φ = 12101022111322.

The previous prime is 12101022111301. The next prime is 12101022111329. The reversal of 12101022111323 is 32311122010121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12101022111323 - 26 = 12101022111259 is a prime.

It is a super-2 number, since 2×121010221113232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12101022111295 and 12101022111304.

It is not a weakly prime, because it can be changed into another prime (12101022111329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050511055661 + 6050511055662.

It is an arithmetic number, because the mean of its divisors is an integer number (6050511055662).

Almost surely, 212101022111323 is an apocalyptic number.

12101022111323 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101022111323 is an equidigital number, since it uses as much as digits as its factorization.

12101022111323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 12101022111323 its reverse (32311122010121), we get a palindrome (44412144121444).

The spelling of 12101022111323 in words is "twelve trillion, one hundred one billion, twenty-two million, one hundred eleven thousand, three hundred twenty-three".