Base | Representation |
---|---|
bin | 11011100000111100011101… |
… | …100101110000010001100010 |
3 | 120212110120001120222110121212 |
4 | 123200330131211300101202 |
5 | 111330121414200013442 |
6 | 1105211440002150122 |
7 | 34326525226316534 |
oct | 3340743545602142 |
9 | 525416046873555 |
10 | 121011200001122 |
11 | 3561561a710782 |
12 | 116a4946052342 |
13 | 526a3cbba77c2 |
14 | 21c4d8ab69854 |
15 | decba42b5a82 |
hex | 6e0f1d970462 |
121011200001122 has 4 divisors (see below), whose sum is σ = 181516800001686. Its totient is φ = 60505600000560.
The previous prime is 121011200001113. The next prime is 121011200001151. The reversal of 121011200001122 is 221100002110121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 94879463690881 + 26131736310241 = 9740609^2 + 5111921^2 .
It is a junction number, because it is equal to n+sod(n) for n = 121011200001097 and 121011200001106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30252800000279 + ... + 30252800000282.
Almost surely, 2121011200001122 is an apocalyptic number.
121011200001122 is a deficient number, since it is larger than the sum of its proper divisors (60505600000564).
121011200001122 is an equidigital number, since it uses as much as digits as its factorization.
121011200001122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60505600000563.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 121011200001122 its reverse (221100002110121), we get a palindrome (342111202111243).
The spelling of 121011200001122 in words is "one hundred twenty-one trillion, eleven billion, two hundred million, one thousand, one hundred twenty-two".
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