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121011200001122 = 260505600000561
BaseRepresentation
bin11011100000111100011101…
…100101110000010001100010
3120212110120001120222110121212
4123200330131211300101202
5111330121414200013442
61105211440002150122
734326525226316534
oct3340743545602142
9525416046873555
10121011200001122
113561561a710782
12116a4946052342
13526a3cbba77c2
1421c4d8ab69854
15decba42b5a82
hex6e0f1d970462

121011200001122 has 4 divisors (see below), whose sum is σ = 181516800001686. Its totient is φ = 60505600000560.

The previous prime is 121011200001113. The next prime is 121011200001151. The reversal of 121011200001122 is 221100002110121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 94879463690881 + 26131736310241 = 9740609^2 + 5111921^2 .

It is a junction number, because it is equal to n+sod(n) for n = 121011200001097 and 121011200001106.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30252800000279 + ... + 30252800000282.

Almost surely, 2121011200001122 is an apocalyptic number.

121011200001122 is a deficient number, since it is larger than the sum of its proper divisors (60505600000564).

121011200001122 is an equidigital number, since it uses as much as digits as its factorization.

121011200001122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60505600000563.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 121011200001122 its reverse (221100002110121), we get a palindrome (342111202111243).

The spelling of 121011200001122 in words is "one hundred twenty-one trillion, eleven billion, two hundred million, one thousand, one hundred twenty-two".

Divisors: 1 2 60505600000561 121011200001122