Base | Representation |
---|---|
bin | 11011100000111101001110… |
… | …000000000101011101010011 |
3 | 120212110122011012021221202021 |
4 | 123200331032000011131103 |
5 | 111330130100111210003 |
6 | 1105212052334432311 |
7 | 34326554321062465 |
oct | 3340751600053523 |
9 | 525418135257667 |
10 | 121012012210003 |
11 | 356159a7130292 |
12 | 116a4b32062697 |
13 | 526a4cb243785 |
14 | 21c5026992135 |
15 | decc007502bd |
hex | 6e0f4e005753 |
121012012210003 has 2 divisors, whose sum is σ = 121012012210004. Its totient is φ = 121012012210002.
The previous prime is 121012012209973. The next prime is 121012012210031. The reversal of 121012012210003 is 300012210210121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121012012210003 - 229 = 121011475339091 is a prime.
It is a super-2 number, since 2×1210120122100032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121012012210043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60506006105001 + 60506006105002.
It is an arithmetic number, because the mean of its divisors is an integer number (60506006105002).
Almost surely, 2121012012210003 is an apocalyptic number.
121012012210003 is a deficient number, since it is larger than the sum of its proper divisors (1).
121012012210003 is an equidigital number, since it uses as much as digits as its factorization.
121012012210003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 121012012210003 its reverse (300012210210121), we get a palindrome (421024222420124).
The spelling of 121012012210003 in words is "one hundred twenty-one trillion, twelve billion, twelve million, two hundred ten thousand, three".
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