Base | Representation |
---|---|
bin | 1011000000011000100001… |
… | …0100101100101010110011 |
3 | 1120211212100010112211001212 |
4 | 2300012020110230222303 |
5 | 3041231234230000201 |
6 | 41423115155350335 |
7 | 2356166156555654 |
oct | 260061024545263 |
9 | 46755303484055 |
10 | 12101210000051 |
11 | 3946104626947 |
12 | 14353668b23ab |
13 | 69a1a6ab5393 |
14 | 2db9b761352b |
15 | 15eba84bdabb |
hex | b018852cab3 |
12101210000051 has 2 divisors, whose sum is σ = 12101210000052. Its totient is φ = 12101210000050.
The previous prime is 12101209999999. The next prime is 12101210000059. The reversal of 12101210000051 is 15000001210121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12101210000051 - 218 = 12101209737907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12101209999990 and 12101210000035.
It is not a weakly prime, because it can be changed into another prime (12101210000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050605000025 + 6050605000026.
It is an arithmetic number, because the mean of its divisors is an integer number (6050605000026).
Almost surely, 212101210000051 is an apocalyptic number.
12101210000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12101210000051 is an equidigital number, since it uses as much as digits as its factorization.
12101210000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 12101210000051 its reverse (15000001210121), we get a palindrome (27101211210172).
The spelling of 12101210000051 in words is "twelve trillion, one hundred one billion, two hundred ten million, fifty-one", and thus it is an aban number.
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