Base | Representation |
---|---|
bin | 1011000000011000111001… |
… | …0110000001100101111001 |
3 | 1120211212121011121201022021 |
4 | 2300012032112001211321 |
5 | 3041231441104324233 |
6 | 41423133204354441 |
7 | 2356201524262045 |
oct | 260061626014571 |
9 | 46755534551267 |
10 | 12101311011193 |
11 | 3946156649028 |
12 | 14353946a5a21 |
13 | 69a1c19c11a1 |
14 | 2db9c6bc9025 |
15 | 15ebb22c2e2d |
hex | b018e581979 |
12101311011193 has 2 divisors, whose sum is σ = 12101311011194. Its totient is φ = 12101311011192.
The previous prime is 12101311011079. The next prime is 12101311011259. The reversal of 12101311011193 is 39111011310121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10550855211264 + 1550455799929 = 3248208^2 + 1245173^2 .
It is a cyclic number.
It is not a de Polignac number, because 12101311011193 - 241 = 9902287755641 is a prime.
It is not a weakly prime, because it can be changed into another prime (12101311011793) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050655505596 + 6050655505597.
It is an arithmetic number, because the mean of its divisors is an integer number (6050655505597).
Almost surely, 212101311011193 is an apocalyptic number.
It is an amenable number.
12101311011193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12101311011193 is an equidigital number, since it uses as much as digits as its factorization.
12101311011193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 25.
The spelling of 12101311011193 in words is "twelve trillion, one hundred one billion, three hundred eleven million, eleven thousand, one hundred ninety-three".
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