Search a number
-
+
12102003411034 = 26051001705517
BaseRepresentation
bin1011000000011011011110…
…0111010100100001011010
31120211221101102111021022211
42300012313213110201122
53041234400333123114
641423330021105334
72356224632500345
oct260066747244132
946757342437284
1012102003411034
1139464814772a9
12143554855824a
1369a2a229c134
142dba50b4545c
1515ec02e936c4
hexb01b79d485a

12102003411034 has 4 divisors (see below), whose sum is σ = 18153005116554. Its totient is φ = 6051001705516.

The previous prime is 12102003410971. The next prime is 12102003411109. The reversal of 12102003411034 is 43011430020121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8912296710409 + 3189706700625 = 2985347^2 + 1785975^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12102003410996 and 12102003411014.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3025500852757 + ... + 3025500852760.

Almost surely, 212102003411034 is an apocalyptic number.

12102003411034 is a deficient number, since it is larger than the sum of its proper divisors (6051001705520).

12102003411034 is an equidigital number, since it uses as much as digits as its factorization.

12102003411034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6051001705519.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12102003411034 its reverse (43011430020121), we get a palindrome (55113433431155).

The spelling of 12102003411034 in words is "twelve trillion, one hundred two billion, three million, four hundred eleven thousand, thirty-four".

Divisors: 1 2 6051001705517 12102003411034