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12102017 is a prime number
BaseRepresentation
bin101110001010…
…100110000001
3211202211211212
4232022212001
511044231032
61111215505
7204602564
oct56124601
924684755
1012102017
116916474
124077595
132679575
1418704db
1510e0bb2
hexb8a981

12102017 has 2 divisors, whose sum is σ = 12102018. Its totient is φ = 12102016.

The previous prime is 12102001. The next prime is 12102023. The reversal of 12102017 is 71020121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11182336 + 919681 = 3344^2 + 959^2 .

It is an emirp because it is prime and its reverse (71020121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12102017 - 24 = 12102001 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12101992 and 12102010.

It is not a weakly prime, because it can be changed into another prime (12102067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051008 + 6051009.

It is an arithmetic number, because the mean of its divisors is an integer number (6051009).

Almost surely, 212102017 is an apocalyptic number.

It is an amenable number.

12102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102017 is an equidigital number, since it uses as much as digits as its factorization.

12102017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 12102017 is about 3478.7953374696. The cubic root of 12102017 is about 229.5897981461.

Adding to 12102017 its reverse (71020121), we get a palindrome (83122138).

The spelling of 12102017 in words is "twelve million, one hundred two thousand, seventeen".