Base | Representation |
---|---|
bin | 1011000000011011100010… |
… | …1111011111101110110001 |
3 | 1120211221102202002112001220 |
4 | 2300012320233133232301 |
5 | 3041234420204100223 |
6 | 41423331534415253 |
7 | 2356225252351455 |
oct | 260067057375661 |
9 | 46757382075056 |
10 | 12102022331313 |
11 | 394649111a3a2 |
12 | 1435552961529 |
13 | 69a2a6194c75 |
14 | 2dba5346c665 |
15 | 15ec0497e6e3 |
hex | b01b8bdfbb1 |
12102022331313 has 4 divisors (see below), whose sum is σ = 16136029775088. Its totient is φ = 8068014887540.
The previous prime is 12102022331297. The next prime is 12102022331327. The reversal of 12102022331313 is 31313322020121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12102022331313 - 24 = 12102022331297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12102022331813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2017003721883 + ... + 2017003721888.
It is an arithmetic number, because the mean of its divisors is an integer number (4034007443772).
Almost surely, 212102022331313 is an apocalyptic number.
It is an amenable number.
12102022331313 is a deficient number, since it is larger than the sum of its proper divisors (4034007443775).
12102022331313 is an equidigital number, since it uses as much as digits as its factorization.
12102022331313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4034007443774.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 12102022331313 its reverse (31313322020121), we get a palindrome (43415344351434).
The spelling of 12102022331313 in words is "twelve trillion, one hundred two billion, twenty-two million, three hundred thirty-one thousand, three hundred thirteen".
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