Base | Representation |
---|---|
bin | 111000010110101011… |
… | …1111000100111101001 |
3 | 102120101010002020201201 |
4 | 1300231113320213221 |
5 | 3440322200221413 |
6 | 131332421244201 |
7 | 11512665514651 |
oct | 1605527704751 |
9 | 376333066651 |
10 | 121020320233 |
11 | 473628a788a |
12 | 1b555563661 |
13 | b5486ba657 |
14 | 5c00a63361 |
15 | 323484c9dd |
hex | 1c2d5f89e9 |
121020320233 has 2 divisors, whose sum is σ = 121020320234. Its totient is φ = 121020320232.
The previous prime is 121020320221. The next prime is 121020320243. The reversal of 121020320233 is 332023020121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61069777129 + 59950543104 = 247123^2 + 244848^2 .
It is a cyclic number.
It is not a de Polignac number, because 121020320233 - 229 = 120483449321 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121020320233.
It is not a weakly prime, because it can be changed into another prime (121020320243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510160116 + 60510160117.
It is an arithmetic number, because the mean of its divisors is an integer number (60510160117).
Almost surely, 2121020320233 is an apocalyptic number.
It is an amenable number.
121020320233 is a deficient number, since it is larger than the sum of its proper divisors (1).
121020320233 is an equidigital number, since it uses as much as digits as its factorization.
121020320233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 121020320233 its reverse (332023020121), we get a palindrome (453043340354).
The spelling of 121020320233 in words is "one hundred twenty-one billion, twenty million, three hundred twenty thousand, two hundred thirty-three".
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