Base | Representation |
---|---|
bin | 1011000000011011111000… |
… | …0110010110110010000011 |
3 | 1120211221200000012211112001 |
4 | 2300012332012112302003 |
5 | 3041240111211210201 |
6 | 41423344505044431 |
7 | 2356230423330553 |
oct | 260067606266203 |
9 | 46757600184461 |
10 | 12102112210051 |
11 | 3946527928646 |
12 | 1435578a86717 |
13 | 69a2bb9a3956 |
14 | 2dba61387163 |
15 | 15ec0c7d5301 |
hex | b01be196c83 |
12102112210051 has 2 divisors, whose sum is σ = 12102112210052. Its totient is φ = 12102112210050.
The previous prime is 12102112210037. The next prime is 12102112210087. The reversal of 12102112210051 is 15001221120121.
It is a weak prime.
It is an emirp because it is prime and its reverse (15001221120121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12102112210051 - 235 = 12067752471683 is a prime.
It is a super-2 number, since 2×121021122100512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12102112210021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051056105025 + 6051056105026.
It is an arithmetic number, because the mean of its divisors is an integer number (6051056105026).
Almost surely, 212102112210051 is an apocalyptic number.
12102112210051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12102112210051 is an equidigital number, since it uses as much as digits as its factorization.
12102112210051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 12102112210051 its reverse (15001221120121), we get a palindrome (27103333330172).
The spelling of 12102112210051 in words is "twelve trillion, one hundred two billion, one hundred twelve million, two hundred ten thousand, fifty-one".
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