Base | Representation |
---|---|
bin | 10001100111000110001… |
… | …101110010001000000100 |
3 | 11021200202201002111212002 |
4 | 101213012031302020010 |
5 | 124312003043442012 |
6 | 2323544032244432 |
7 | 153302110265234 |
oct | 21470615621004 |
9 | 4250681074762 |
10 | 1210211312132 |
11 | 42727a810029 |
12 | 1766693a0718 |
13 | 8a178cc0334 |
14 | 42808775cc4 |
15 | 217313d97c2 |
hex | 119c6372204 |
1210211312132 has 12 divisors (see below), whose sum is σ = 2118044205900. Its totient is φ = 605055824736.
The previous prime is 1210211312113. The next prime is 1210211312137. The reversal of 1210211312132 is 2312131120121.
It can be written as a sum of positive squares in 2 ways, for example, as 1159033109056 + 51178203076 = 1076584^2 + 226226^2 .
It is a super-2 number, since 2×12102113121322 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1210211312137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12403163 + ... + 12500354.
It is an arithmetic number, because the mean of its divisors is an integer number (176503683825).
Almost surely, 21210211312132 is an apocalyptic number.
It is an amenable number.
1210211312132 is a deficient number, since it is larger than the sum of its proper divisors (907832893768).
1210211312132 is a wasteful number, since it uses less digits than its factorization.
1210211312132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24915670 (or 24915668 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1210211312132 its reverse (2312131120121), we get a palindrome (3522342432253).
The spelling of 1210211312132 in words is "one trillion, two hundred ten billion, two hundred eleven million, three hundred twelve thousand, one hundred thirty-two".
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