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1210213221953 is a prime number
BaseRepresentation
bin10001100111000110010…
…101000100011001000001
311021200202211200112122012
4101213012111010121001
5124312004041100303
62323544141222305
7153302132441231
oct21470625043101
94250684615565
101210213221953
114272808a499a
12176669b61995
138a17950b6c8
1442808b11cc1
15217316655d8
hex119c6544641

1210213221953 has 2 divisors, whose sum is σ = 1210213221954. Its totient is φ = 1210213221952.

The previous prime is 1210213221941. The next prime is 1210213222013. The reversal of 1210213221953 is 3591223120121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1108457325889 + 101755896064 = 1052833^2 + 318992^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210213221953 - 238 = 935335315009 is a prime.

It is a super-2 number, since 2×12102132219532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1210213224953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605106610976 + 605106610977.

It is an arithmetic number, because the mean of its divisors is an integer number (605106610977).

Almost surely, 21210213221953 is an apocalyptic number.

It is an amenable number.

1210213221953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210213221953 is an equidigital number, since it uses as much as digits as its factorization.

1210213221953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 32.

The spelling of 1210213221953 in words is "one trillion, two hundred ten billion, two hundred thirteen million, two hundred twenty-one thousand, nine hundred fifty-three".