Base | Representation |
---|---|
bin | 10001100111000110011… |
… | …001010011101001010011 |
3 | 11021200202220202222201111 |
4 | 101213012121103221103 |
5 | 124312004332124021 |
6 | 2323544221114151 |
7 | 153302145046405 |
oct | 21470631235123 |
9 | 4250686688644 |
10 | 1210214333011 |
11 | 427281493722 |
12 | 17666a3b8957 |
13 | 8a17980a338 |
14 | 42808d20b75 |
15 | 217317d48e1 |
hex | 119c6653a53 |
1210214333011 has 2 divisors, whose sum is σ = 1210214333012. Its totient is φ = 1210214333010.
The previous prime is 1210214332979. The next prime is 1210214333051. The reversal of 1210214333011 is 1103334120121.
It is a weak prime.
It is an emirp because it is prime and its reverse (1103334120121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1210214333011 - 25 = 1210214332979 is a prime.
It is a super-2 number, since 2×12102143330112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1210214333051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605107166505 + 605107166506.
It is an arithmetic number, because the mean of its divisors is an integer number (605107166506).
Almost surely, 21210214333011 is an apocalyptic number.
1210214333011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210214333011 is an equidigital number, since it uses as much as digits as its factorization.
1210214333011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1210214333011 its reverse (1103334120121), we get a palindrome (2313548453132).
The spelling of 1210214333011 in words is "one trillion, two hundred ten billion, two hundred fourteen million, three hundred thirty-three thousand, eleven".
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