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12102419993 is a prime number
BaseRepresentation
bin10110100010101110…
…00100011000011001
31011020102211122011112
423101113010120121
5144241204414433
65320524510105
7605623605206
oct132127043031
934212748145
1012102419993
1151505562a4
1224190ab335
1311ab444981
1482b47ccad
154ac752348
hex2d15c4619

12102419993 has 2 divisors, whose sum is σ = 12102419994. Its totient is φ = 12102419992.

The previous prime is 12102419981. The next prime is 12102419999. The reversal of 12102419993 is 39991420121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10361611264 + 1740808729 = 101792^2 + 41723^2 .

It is an emirp because it is prime and its reverse (39991420121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12102419993 - 28 = 12102419737 is a prime.

It is a super-2 number, since 2×121024199932 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12102419993.

It is not a weakly prime, because it can be changed into another prime (12102419999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051209996 + 6051209997.

It is an arithmetic number, because the mean of its divisors is an integer number (6051209997).

Almost surely, 212102419993 is an apocalyptic number.

It is an amenable number.

12102419993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102419993 is an equidigital number, since it uses as much as digits as its factorization.

12102419993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992, while the sum is 41.

The spelling of 12102419993 in words is "twelve billion, one hundred two million, four hundred nineteen thousand, nine hundred ninety-three".